Python开发桌面小程序功能_python_
当使用桌面应用程序的时候，
有没有那么一瞬间，
想学习一下桌面应用程序开发？
建议此次课程大家稍作了解不要浪费太多时间，
因为没有哪家公司会招聘以为Python程序员开发桌面程序吧？
开发环境：
- Python 3.6
- Pycharm
代码
界面设置
导入模块
import tkinter as tk
实例化一个窗体对象
root = tk.Tk()
标题
root.title('计算器') 大小以及出现的位置
root.geometry("295x280+150+150") 透明度
root.attributes("-alpha", 0.9) 背景
root["background"] = "#ffffff"
标签
lable1 = tk.Label(root, textvariable=result_num, width=20, height=2, font=('宋体', 20), justify='left', background='#ffffff', anchor='se') 布局
lable1.grid(padx=4, pady=4, row=0, column=0, columnspan=4)
按钮
button_clear = tk.Button(root, text='C', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: clear()) button_back = tk.Button(root, text='←', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: back()) button_division = tk.Button(root, text='/', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('/')) button_multiplication = tk.Button(root, text='x', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('*')) button_clear .grid(padx=4, row=1, column=0) button_back .grid(padx=4, row=1, column=1) button_division .grid(padx=4, row=1, column=2) button_multiplication .grid(padx=4, row=1, column=3) button_seven = tk.Button(root, text='7', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('7')) button_eight = tk.Button(root, text='8', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('8')) button_nine = tk.Button(root, text='9', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('9')) button_subtraction = tk.Button(root, text='—', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('-')) button_seven .grid(padx=4, row=2, column=0) button_eight .grid(padx=4, row=2, column=1) button_nine .grid(padx=4, row=2, column=2) button_subtraction .grid(padx=4, row=2, column=3) button_four = tk.Button(root, text='4', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('4')) button_four.grid(padx=4, pady=4, row=3, column=0) button_five = tk.Button(root, text='5', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('5')) button_five.grid(padx=4, row=3, column=1) button_six = tk.Button(root, text='6', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('6')) button_six.grid(padx=4, row=3, column=2) button_addition = tk.Button(root, text='+', width=5, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: operator('+')) button_addition.grid(padx=4, row=3, column=3) button_one = tk.Button(root, text='1', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('1')) button_one.grid(padx=4, row=4, column=0) button_two = tk.Button(root, text='2', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('2')) button_two.grid(padx=4, row=4, column=1) button_three = tk.Button(root, text='3', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('3')) button_three.grid(padx=4, row=4, column=2) button_equal = tk.Button(root, text='=', width=5, height=3, font=('宋体', 16), relief='flat', background='#C0C0C0', command=lambda: equal()) button_equal.grid(padx=4, row=4, rowspan=5, column=3) button_zero = tk.Button(root, text='0', width=12, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('0')) button_zero.grid(padx=4, pady=4, row=5, column=0, columnspan=2) button_decimal = tk.Button(root, text='.', width=5, font=('宋体', 16), relief='flat', background='#FFDEAD', command=lambda: append_num('.')) button_decimal.grid(padx=4, row=5, column=2) 现在得出界面效果
功能
添加数字
def append_num(i): lists.append(i) result_num.set(''.join(lists)) 选择运算符号
def operator(i): if len(lists) > 0: if lists[-1] in ['+', '-', '*', '/']: lists[-1] = i else: lists.append(i) result_num.set(''.join(lists)) 清零
def clear(): lists.clear() result_num.set(0)
退格
def back(): del lists[-1] result_num.set(lists)
等号
def equal(): a = ''.join(lists) end_num = eval(a) result_num.set(end_num) lists.clear() lists.append(str(end_num))
定义一个列表收集输入的内容
lists = [] result_num = tk.StringVar() result_num.set(0)
最后运行代码，效果如下图
先试试
运算得出结果
